(1)16(x-y)^2-9(x+y)^2

2个回答

  • (1)16(x-y)^2-9(x+y)^2

    =[4(x-y)]^2-[3(x+y)]^2

    =[4(x-y)-3(x+y)]^2

    =(x-7y)^2

    (2)4(2p+3q)^2-(3p-q)^2

    =[2(2p+3q)]^2-(3p-q)^2

    =[2(2p+3q)-(3p-q)]^2

    =(p+7q)^2

    (3)169(a-b)^2-196(a+b)^2

    =[13(a-b)]^2-[14(a+b)]^2

    =[13(a-b)-14(a+b)]^2

    =(a+27b)^2

    【(a+1/2)^2+(a-1/2)^2】*(2a^2-1/2b^2)

    =[(a+1/2)+(a-1/2)]^2*(2a+1)(2a-1)/2b^2

    =(2a)^2*(2a+1)(2a-1)/2b^2

    =a^2(2a+1)(2a-1)/b^2

    其中a=-3,b=4

    原式=(-3)^2[2*(-3)+1][2*(-3)-1]/4^2

    =9*(-5)*(-7)/16

    =305/16