Question

已知【a-2分之1】的2次方+|a+b+1|=0求代数式-3（a的2次方-3）-2（-a的2次方+b)的值

Answer 1

(a-1/2)^2+|a+b+1|=0

a=1/2 b=-3/2

-3(a^2-3)-2(-a^2+b)

=-3(1/4-3)-2(-1/4-3/2)

=-3*(-11/4)-2(-7/4)

=33/4+14/4

=47/4