Question

初二分式计算题,(x-3/2x-4)/[(5/x-2)-x-2]

Answer 1

原式={(x-3/2x-4)}/{(5-x^2+2x-2x+4)/(x-2)}

={(x-3/2x-4)}/{(9-x^2)/(x-2)}

={x-3}/{2(x-2)}·{x-2}/{9-x^2}

={x-3}/{2(x-2)}·{x-2}/{(3+x)(3-x)}

=-{x-3}/{2(x-2)}·{x-2}/{(3+x)(x-3)}

=-1/2x+6

注：{ }表示分子或分母