|x+2|+(y-1)²=0
绝对值项与平方项均恒非负,两者之和=0,两者分别=0
x+2=0 x=-2
y-1=0 y=1
A-B
=-3x+2y²-(x²-2x-y²)
=-x²-x+3y²
=-(-2)²-(-2)+3×1²
=-4+2+3
=1
|x+2|+(y-1)²=0
绝对值项与平方项均恒非负,两者之和=0,两者分别=0
x+2=0 x=-2
y-1=0 y=1
A-B
=-3x+2y²-(x²-2x-y²)
=-x²-x+3y²
=-(-2)²-(-2)+3×1²
=-4+2+3
=1