Question

(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程

Answer 1

1/{(x-1)(x-2)} = 1/{(x-4)(x-5)}

首先,分母不为零,∴x ≠ 1 , 2 , 4 ,5

通分：

(x-4)(x-5) = (x-1)(x-2)

x^2-9x+20=x^2-3x+2

6x=18

x=3