Question

已知：a的平方-5a-2003=0,求(a-2)的三次方-(a-1)的平方+1/(a-2)的值

Answer 1

a的平方-5a-2003=0

a^2-5a=2003

[(a-2)的三次方-(a-1)的平方+1]/(a-2)的值

=(a-2)^2-[(a^2-2a+1)-1]/(a-2)

=(a^2-4a+4)-a(a-2)/(a-2)

=(a^2-4a+4)-a

=a^2-5a+4

=2003+4

=2007