Question

已知(x-1)的平方=ax的五次方+bx的4次方+cx的3次方+dx的2次方+ex+f.(1)求a

Answer 1

(x-1)^2=ax^5+bx^4+cx^3+dx^2+ex+f

(x-1)^2=x^2-2x+1

所以a=0.b=0,c =0,d=1,e =-2,f=1

a+b+c+d+e+f=1-2+1=0

b+d=0+1=1