(1)x-2y=-9,y-z=3,2z+x=47.
1个回答
(1)22 15.5 12.5
(2) 2 3 1
(3) 2 1 3
(4) 4 5 15
(5) 70 42 20
一般解法就是先消掉一个未知数,然后解二元方程
相关问题
x-2y=9 x-z=3 2z+x=47
解方程组x-2y=-9 y-z=3 2z+x=47
解三元一次方程组,方程组1:方程组2:X-2Y=-9 3X-Y+Z=4Y-Z=3 2X+3Y-Z=122Z+X=47;
1:7x+2y-z=7 2:6x-y+z=7 3:4x+3y+z=9 1:9x+4y+z+10 2:-9X+2y+3z=
(1)3x+4y=15 2y-z=2 x+2z=9 (2) x+y+z=8 2x+3y-z=6 3x-y+z=8 (3)
已知x+2y+3z=54,3x+2y+2z=47,2x+y+z=31,求代数式x+y+z的值
x+y+z=15 2x+3y+4z=47 3x+4y+5z=62
x+y+z=15 2x+3y+4z=47 3x+4y+5z=62
已知x+2y+3z=54,3x+y+2z=47,2x+3y+z=31,那么代数式x+y+z的值是( )
已知x+2y+3z=54,3x+y+2z=47,2x+3y+z=31,那么代数式x+y+z的值是( )