A：由mx^2≥0,即有mx^2+1＞0对任意x都满足,所以解集为R,所以是真命题
可知B是假命题,所以m＞1
,因a/x1＞a/x2是假命题,
所以a/x1≤a/x2,x1＜x2＜0,x1x2＞0
x1x2*a/x1≤x1x2*a/x2
ax2≤ax1
a(x2-x1)≤0
a≤0
像下面这两个含参的不等式应该怎么解
A：由mx^2≥0,即有mx^2+1＞0对任意x都满足,所以解集为R,所以是真命题
可知B是假命题,所以m＞1
,因a/x1＞a/x2是假命题,
所以a/x1≤a/x2,x1＜x2＜0,x1x2＞0
x1x2*a/x1≤x1x2*a/x2
ax2≤ax1
a(x2-x1)≤0
a≤0