对数基本题去方法log2(log2 32-log2 3/4+log2 6)算到这里卡主了log2(log2 (32/(3
1个回答
log2(log2 (32/(3/4)*6))
=log2(log2 (32*(4/3)*6))
=log2(log2 (256))
=log2(log2 (2^16))
=log2 16
=4
相关问题
求值:log2(32)+log2(6)-log2(3/4)
对数函数计算 log4 3·log9 2-log1/2 4次根号32
化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32
求值 3^2-log3(2)= log7(log5(log2(32)))=?
2log3^2-log3^(32/9)+log3^8
2log3^2-log3^(32/9)+log3^8-5log5^3=
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
计算 2log3 2-log32/9+log3 8-5^log5 3
怎么把log2 42 -log 2 32的log2提出去
(log6^2)^2+(log6^3)*(log6^4)+(log6^3)^2