log(a^n)M=1/n*（logaM）,
Log(2^2)3=1/2log（2）3
log(a^n)M=?比如Log(2^2)3=?
1个回答
相关问题
-
log以a为底2=m,log以a为底3=n,则a^(2m+n)=
-
lg a^2=m log a 3=n a^(2m+n)+=?
-
若m=1/log5(19)+2/log3(19)+3/log2(19),n=1/log2(π)+1/log5(π),则m
-
换底公式推导过程1.log(a)(b)=1/log(b)(a) 2.log(a^n)(b^m)=m/n*[log(a)(
-
log a (m^n)=(log a m)^n?
-
帮我看一眼这些公式对不对?1.a^log_a^b =b2.log_a^〖m×n〗= log_a^m+log_a^n3.l
-
已知2^m=3 log2 5=n,则log15 2=
-
化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根)
-
log(a)M+log(a)N=?
-
(log(a)/(N))/(log(a)/(M))=?