Question

很关键的数学题,谢如图,三角形ABC中,∠A= 52°,BE平分∠ABC,CE平分∠ACD,BE、CE相交于点E,则∠B

Answer 1

∠BEC = 180-∠EBC-∠ECB=180-(∠ABC+∠ACB)/2=180-(180-∠A)/2

=90+∠A/2=90+26=116