由题,设a/b=c/d=…=m/n=k
则,a=bk,c=dk,……,m=nk
又,b+d+…+n≠0
所以,
(a+c+…+m)/(b+d+…+n)
=(bk+dk+…+nk)/(b+d+……+n)
=k
=a/b
所以,(a+c+…+m)/(b+d+…+n)=a/
由题,设a/b=c/d=…=m/n=k
则,a=bk,c=dk,……,m=nk
又,b+d+…+n≠0
所以,
(a+c+…+m)/(b+d+…+n)
=(bk+dk+…+nk)/(b+d+……+n)
=k
=a/b
所以,(a+c+…+m)/(b+d+…+n)=a/