Question

一道关于分式的初二数学题已知y=(x^-3xy-2y^)÷2y,求y:x的值

Answer 1

y=(x^2-3xy-2y^2)÷2y

x^2-3xy-2y^2=2y^2

x^2-3xy-4y^2=0

(x-4y)(x+y)=0

x=4y或x=-y

所以y:x=1/4或-1