令3 x=t,x=log 3t,
∴f(t)=2log 3t•log 23+11
=2log 2t+11.
∴f(2)+f(4)+f(8)+f(16)+f(32)+f(64)
=2(log 22+log 24+log 28+log 216+log 232+log 264)+11×6
=108.
故答案为:108.
令3 x=t,x=log 3t,
∴f(t)=2log 3t•log 23+11
=2log 2t+11.
∴f(2)+f(4)+f(8)+f(16)+f(32)+f(64)
=2(log 22+log 24+log 28+log 216+log 232+log 264)+11×6
=108.
故答案为:108.