急![(3x+y)²-3(3x-y)(x+y)-(x-3y)(x+3y)]÷(2xy)
1个回答
原式=(9x²+6xy+y²-9x²-6xy+3y²-x²+9y²)÷2xy
=13y²÷2xy
=13y/2x
当x=1/2,y=-2时
原式=13乘以-2/2乘以1/2
=-26
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