(1).CH4+H20==(催化重整)=CO+3H2
(2).2C0+4H2==(一定条件)=CH3OCH3+H20
(1)*2+(2)得
左边加左边,右边加右边就是:
2CH4+2H20+2CO+4H2==(一定条件)2CO+6H2+CH3OCH3+H20,两边消去得出正确的答案.
(1).CH4+H20==(催化重整)=CO+3H2
(2).2C0+4H2==(一定条件)=CH3OCH3+H20
(1)*2+(2)得
左边加左边,右边加右边就是:
2CH4+2H20+2CO+4H2==(一定条件)2CO+6H2+CH3OCH3+H20,两边消去得出正确的答案.