Question

参数方程问题（1）求直线y=-x+1与圆｛x=1+cosθ,y=sinθ（θ为参数）的交点坐标（2）抛物线｛x=t,y=

Answer 1

⑴圆:(x-1)^2+y^2=1,把y=-x+1代入圆方程得2(x-1)^2=1,

x1=1+✓2／2,y1=-✓2／2;

x2=1-✓2／2,y2=✓2／2.

⑵抛物线y=x^2,圆x^2+y^2=2,

y^2+y-2=0,(y-1)(y+2)=0,

y1=1,x1=1或x1=-1,相应角度为45度和135度,t=±1;

y2=-2,不成立.