Question

已知Lim[(X的平方+1/X+1)-ax-b]=0,且X趋近于无穷大,求a和b.

Answer 1

lim{[(x^2+1)/(x+1)-ax-b]/x}=0

lim{(x^2+1)/(x^2+x)-a-b/x}=0

1-a=0

a=1

lim[(x^2+1)/(x+1)-x-b]=0

lim[(1-x)/(x+1)-b]=0

-1-b=0

b=-1