y=cos^2 x+1/2sin2x
=1/2cos2x+1/2sin2x
=1/2*根号2*cos(45°+2x)
而,y=cosx 的单调性为(0°,90°)单调递减
由此,可知:
0°+360°≤45°+2x≤90°+360°
于是解出x范围!
y=cos^2 x+1/2sin2x
=1/2cos2x+1/2sin2x
=1/2*根号2*cos(45°+2x)
而,y=cosx 的单调性为(0°,90°)单调递减
由此,可知:
0°+360°≤45°+2x≤90°+360°
于是解出x范围!