Question

求∫e的根号下X+1次方 dx,拜谢.

Answer 1

换元法,令√(x+1)=t

x=t^2-1

dx=2tdt

∫e^√(x+1)dx

=∫e^t*2tdt

=∫2tde^t

=2te^t-2∫e^tdt

=2te^t-2e^t+C