Question

若a,b为有理数,且a-2的绝对值+（b+3）的2次方=0,求6的a次方的值

Answer 1

|a-2|+(b+3)^2=0

|a-2|>=0,(b+3)^2>=0

a-2=0,b+3=0,

a=2,b=-3.

6^a=36