∵BA⊥AD,BC⊥DC
∴∠A=∠C=90°
∴∠B+∠D=360°-(∠A+∠C)=360°-(90°+90°)=180°
∵∠B=1/2∠D
即∠D=2∠B
∴2∠B+∠B=180°
∠B=60°
∴∠D=2∠B=120°