Question

逻辑函数化简：(A'+B)(A'CD+CD)AB'

Answer 1

(A'+B)(A'CD+CD)AB'

＝(A'+B)CD(A'+1)AB'

=(A'+B)AB'CD

=(A'AB'+AB'B)CD

=(0+0)CD

=0.

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应用交换律还可更简单：

(A'+B)(A'CD+CD)AB'

=AB'(A'+B)(A'CD+CD)

=(A'AB'+AB'B)(A'CD+CD)

=(0+0)(A'CD+CD)

=0.

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