Question

解方程:(x-1)(x-2)(x+2)(x+3)=60

Answer 1

数学之美团为你解答

(x-1)(x-2)(x+2)(x+3)=60

[(x-1)(x+2)] [(x-2)(x+3)] = 60

(x²+x-2)(x²+x-6)=60

(x²+x)²-8(x²+x)+12=60

(x²+x)²-8(x²+x)-48=0

(x²+x-12)(x²+x+4)=0

x²+x-12= 0 或 x²+x+4=0

x²+x-12= 0 即 (x+4)(x-3)=0,得x₁=-4；x₂=3；

x²+x+4=0 ,Δ