设小刚的路程为:S1,小明的为S2,则有:S1=at+1450S2=bt+1600200秒时小刚到达终点,300秒时小明到达终点可得:200a+1450=300b+1600·····························1100秒时小刚追上了小明...
设小刚的路程为:S1,小明的为S2,则有:S1=at+1450S2=bt+1600200秒时小刚到达终点,300秒时小明到达终点可得:200a+1450=300b+1600·····························1100秒时小刚追上了小明...