Question

计算：（1+1/2）[1+1/(2^2)][1+1/(2^4)][1+1/(2^8)]+1/(2^15)

Answer 1

5x+b

余式为0

(17x^2-3x+4)-(ax^2+6x+c)=(5x+b)(2x+1)

(17-a)x^2+(-9)x+(4-c)=10x^2+(5+2b)+b

所以17-a=10

-9=5+2b

4-c=b

所以a=7,b=-7,c=4-b=11

a-b-c=3

抄者是

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ok!