设甲种溶液的浓度为x,乙钟溶液的浓度为y,得:
(240x+120y)÷(240+120)=8% ①
(80x+160y)÷(80+160)=10% ②
由①得240x+120y=28.8 ③
由②得80x+160y=24 ④
④×3-③得:
360y=43.2
y=0.12=12%;
把y=12%代入④,得:
80x+160×12%=24
80x=4.8
x=6%.
答:甲药液的浓度是6%,乙药液的浓度是12%.
设甲种溶液的浓度为x,乙钟溶液的浓度为y,得:
(240x+120y)÷(240+120)=8% ①
(80x+160y)÷(80+160)=10% ②
由①得240x+120y=28.8 ③
由②得80x+160y=24 ④
④×3-③得:
360y=43.2
y=0.12=12%;
把y=12%代入④,得:
80x+160×12%=24
80x=4.8
x=6%.
答:甲药液的浓度是6%,乙药液的浓度是12%.