Question

已知函数f(x)=log3[1-m(x-2)]/x-3,其图像关于直线x=2对称.(1)求实数m的值； (2)当x∈(3

Answer 1

1,求M的值

y=log{[1-m(x-2)]/(x-3)}

当x=0时,y=log[(1+2m)/(-3)]

当x=4时,y=log(1-2m)

已知其图像关于x=2对称,则：f(0)=f(4)

即：log[(1+2m)/(-3)]=log(1-2m)

===> (1+2m)/(-3)=1-2m

===> 1+2m=-3+6m

===> m=1

2 由(1)知,m=1

所以,y=log[(3-x)/(x-3)]————?!