(1)
f(x)=cos(2x-2派/3)-cos2x
=cos2xcos-2派/3+sin2xsin-2派/3-cos2x
=-1/2cos2x-根3/2sin2x-cos2x
=-3/2cos2x-根3/2sin2x
=根3(-根3/2cos2x-1/2sin2x)
=根3[cos(2x-派/3)]
T=2派/2=派 派
(1)
f(x)=cos(2x-2派/3)-cos2x
=cos2xcos-2派/3+sin2xsin-2派/3-cos2x
=-1/2cos2x-根3/2sin2x-cos2x
=-3/2cos2x-根3/2sin2x
=根3(-根3/2cos2x-1/2sin2x)
=根3[cos(2x-派/3)]
T=2派/2=派 派