Question

sin（x+pai/3)+2sin(x-pai/3)-3^1/2 cos(2pai/3-x)化简得〇,

Answer 1

证明：

原式可化为

sin(x+π/3)+2sin(x-π/3)-√3cos(2π/3-x)=0

左边=1/2×sinx+√3/2×cosx+sinx-√3cosx-√3(-1/2×cosx+√3/2×sinx)

=(1/2+1-3/2)sinx+(√3/2-√3+√3/2)cosx

=0+0

=0

=右边

∴原等式成立