1.1/((1/2)/3+(1/2)/2)=12/5
2.1 1 1
1 1 1
1 1 1
1 1 1
v1 v3 v2
-2.5s-1-2.5s-1-1.5s-1-1.5s-
v1=60/5=12m/s v2=60/3=20m/s
t(v1,v2)=2.5s+1.5s=4s
v3=(v2+v1)/2=16m/s
3.设时间为ts
4*(2+t)=1*1/2*t^2
最远时为而车速度相同时
t`=4/1+2=6s
4*6-1/2*1*4^2=16m
1.1/((1/2)/3+(1/2)/2)=12/5
2.1 1 1
1 1 1
1 1 1
1 1 1
v1 v3 v2
-2.5s-1-2.5s-1-1.5s-1-1.5s-
v1=60/5=12m/s v2=60/3=20m/s
t(v1,v2)=2.5s+1.5s=4s
v3=(v2+v1)/2=16m/s
3.设时间为ts
4*(2+t)=1*1/2*t^2
最远时为而车速度相同时
t`=4/1+2=6s
4*6-1/2*1*4^2=16m