计算:0.8a²b-6ab-1.2a²b+5ab+a²b
2个回答
0.8a²b-6ab-1.2a²b+5ab+a²b
=(0.8-1.2+1)a²b+(-6+5)ab
=0.6a²b-a
相关问题
6a^5b^4÷(4ab)^2+(-1/8ab)(-5a^2b)计算
设实数a、b满足a2-8a+6=0及6b2-8b+1=0,求ab+1ab的值.
计算 (a^2b-ab-a+1)/(ab^2+3ab-b-3)÷(a^2+a_2)/(b^2+b-6)
计算[(a^2-4b^2)/(a^2+4ab+4b^2)]÷[(a^2+ab-6b^2)/(a^2+5ab+6b^2)]
计算√(8a³b²)·[-3/2√(2a²b)]÷√(9ab)(a>0,b>0)
已知a-b=6,ab=—3,求(2a+3b-8ab)-(2ab-5a+7b)-(5ab-3a+6b)的值.
若a+b=5 ,a*b=6,1/a^2+1/b^2=?,a+b/(ab)^2+ a+b/(ab)^2=?
【a²-6ab+9a²/a²-2ab 】/【(5b²/a-2b)-a-2b】-1
(a+b)²+|b-1∕3|=0 求(5a²b-2ab²-3ab)-(2ab+5a
5ab²-{2a²b-3【ab²-2(2ab²+a²b】)},其中a,b满足|a+1|+(b-2)²=0