(1) C6H12
(2) n(A) = 0.5 mol, m(A) = 42 g. n(O2) = 4.5 mol, V(O2) = 100.8 L
(3) CH2 = C(CH3)CH(CH3)CH3; (CH3)2C=C(CH3)2.
所有碳原子在同一平面内的是后者, 加聚:
n (CH3)2C=C(CH3)2 -> -[-C(CH3)2-C(CH3)2-]-n
(4) A为环己烷
本人能力有限, 只能这样解答了. 希望对你有帮助.
(1) C6H12
(2) n(A) = 0.5 mol, m(A) = 42 g. n(O2) = 4.5 mol, V(O2) = 100.8 L
(3) CH2 = C(CH3)CH(CH3)CH3; (CH3)2C=C(CH3)2.
所有碳原子在同一平面内的是后者, 加聚:
n (CH3)2C=C(CH3)2 -> -[-C(CH3)2-C(CH3)2-]-n
(4) A为环己烷
本人能力有限, 只能这样解答了. 希望对你有帮助.