(1)n(HNO 3)=0.5L×0.2mol/L=0.1mol,n(Cu)=
1.92g
64g/mol =0.03mol,
由3Cu+8HNO 3=3Cu(NO 3) 2+2NO↑+4H 2O可知,0.03molCu反应生成0.02molNO,
则生成气体的体积为0.02mol×22.4L/mol=0.448L=448mL,
答:生成气体的体积为448mL;
(2)由3Cu+8HNO 3=3Cu(NO 3) 2+2NO↑+4H 2O可知,生成2molNO时2molHNO 3作氧化剂,被还原,
则生成0.02molNO时有0.02molHNO 3被还原,
答:被还原的HNO 3的物质的量为0.02mol.