Question

ax-x/(x-1)=b比较根号(a+1)和根号b的大小

Answer 1

ax-x/(x-1)=b

ax(x-1)-x=bx

=>ax^2-ax-x-bx=0

ax^2-(a+b+1)x=0

x[ax-(a+b+1)]=0

x>1

所以

ax-(a+b+1)=0

x=(a+b+1)/a>1

=>a+b+1>a

=>根号(a+1)>根号