一共有:[(2000-5)/3+1]/2=333组数,每一组的差=3
(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)
=3+3+3……+3共333个3相加,故:(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)=3*333=999
望君采纳,谢谢~
一共有:[(2000-5)/3+1]/2=333组数,每一组的差=3
(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)
=3+3+3……+3共333个3相加,故:(2000-1997)+(1994-1991)+(1988-1985)···+(14-11)+(8-5)=3*333=999
望君采纳,谢谢~