已知x+3y=7,3x-5y=11,利用因式分解求代数4X2-4XY+Y2
2个回答
4X2-4XY+Y2
=(2x-y)^2
=(1/4)(4x-2y)^2
=(1/4)[(3x-5y)+(x+3y)]^2
=(1/4)(7+11)^2
=81
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