Question

如图,在直角坐标系中,以点a(根号3,0)圆心,以2为半径的圆与x轴相交于点BC,与y轴相交于点D,E

Answer 1

B(-根号3,0) C(3根号3,0) D(0,-3) E(0,3)

1

Y=X方/3+BX+C过(3根号3,0)(0,-3)

若过(-根号3,0)

则-B/(2/3)=-3B/2=根号3 B=-2根号3/3

C/(1/3)=-根号3*3根号3=-9=3C C=-3

即Y=X方/3-2根号3*X/3-3

把(0,-3)代入成立

所以,B在抛物线上

2

连接CD,交对称轴于点P,点P即为所求

P(根号3,-2)

请采纳答案,支持我一下.