(1)y=log2(2x²+3x+1)
y'=[ln(2x²+3x+1)/ln2)]'
=(1/ln2)·[1/(2x²+3x+1)]·(4x+3)
=(4x+3)/[(2x²+3x+1)·ln2]
(2)y=a³xcos(2x+1)(是立方吧)
前导后不导+后导前不导
y'=a³cos(2x+1)-2a³xsin(2x+1)
(1)y=log2(2x²+3x+1)
y'=[ln(2x²+3x+1)/ln2)]'
=(1/ln2)·[1/(2x²+3x+1)]·(4x+3)
=(4x+3)/[(2x²+3x+1)·ln2]
(2)y=a³xcos(2x+1)(是立方吧)
前导后不导+后导前不导
y'=a³cos(2x+1)-2a³xsin(2x+1)