A试管产生10g沉淀
CO2 +Ca(OH)2 ==CaCO3↓+ H20
44 100
x 10g
x=4.4g
10g混合气体含有CO的质量为 10g-4.4g=5.6g
CO+ CuO =加热 = Cu + CO2
28 80 44
5.6g m n
m=16g
n=8.8g
(1)B管内被还原的CuO的质量分数是 16g/20g*100%=80%
CO2 +Ca(OH)2 ==CaCO3↓+ H20
44 100
8.8g y
y=20g
(2)c试管内还能产生20克沉淀
A试管产生10g沉淀
CO2 +Ca(OH)2 ==CaCO3↓+ H20
44 100
x 10g
x=4.4g
10g混合气体含有CO的质量为 10g-4.4g=5.6g
CO+ CuO =加热 = Cu + CO2
28 80 44
5.6g m n
m=16g
n=8.8g
(1)B管内被还原的CuO的质量分数是 16g/20g*100%=80%
CO2 +Ca(OH)2 ==CaCO3↓+ H20
44 100
8.8g y
y=20g
(2)c试管内还能产生20克沉淀