(√12+5√8)√3
= 6 + 10√6
(√48 +√3/4) /√27
= (4√3 +√3/4) /(3√3)
= 4/3 +1/12
= 16/12 +1/12
= 17/12
√(4x)[√(3x)/2-√x/6]
= √(8/3)-√(2/3)
= √8√3/3 -√6/ 3
= 2√6/3 -√6/ 3
= √6/3
(x√y - y√x) / √(xy)
= √x - √y
(√12+5√8)√3
= 6 + 10√6
(√48 +√3/4) /√27
= (4√3 +√3/4) /(3√3)
= 4/3 +1/12
= 16/12 +1/12
= 17/12
√(4x)[√(3x)/2-√x/6]
= √(8/3)-√(2/3)
= √8√3/3 -√6/ 3
= 2√6/3 -√6/ 3
= √6/3
(x√y - y√x) / √(xy)
= √x - √y