Question

已知函数fx=2x+1分之2x-1 ,判断fX的奇偶性

Answer 1

定义域是R

f(-x)=(2^-x-1)/(2^-x+1)

=(1-2^x)/(1+2^x)

=-(2^x-1)/(2^x+1)

=-f(x)

所以f(x)=(2^x-1)/(2^x+1)是奇函数