1)x³-3x²+4
=x³+x²-4x²+4
=x²(x+1)-4(x-1)(x+1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
2)x³-3/4x-1/4
=1/4(4x³-3x-1)
=1/4(4x³-4x+x-1)
=1/4[4x(x+1)(x-1)+(x-1)]
=1/4(x-1)(4x²+4x+1)
=1/4(x-1)(2x+1)²
1)x³-3x²+4
=x³+x²-4x²+4
=x²(x+1)-4(x-1)(x+1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
2)x³-3/4x-1/4
=1/4(4x³-3x-1)
=1/4(4x³-4x+x-1)
=1/4[4x(x+1)(x-1)+(x-1)]
=1/4(x-1)(4x²+4x+1)
=1/4(x-1)(2x+1)²