已知(a+2)²+(3-b)的绝对值=0,
a+2=0 a=-2
3-b=0 b=3
3a²b-【2ab²-b(ab-1/2a²b)+4ab】-2ab
=3a²b-【2ab²-ab²+1/2a²b²+4ab】-2ab
=3a²b-2ab²+ab²-1/2a²b²-4ab-2ab
=3a²b-ab²-1/2a²b²-6ab
=ab(3a-b-1/2ab-6)
=-2×3×【3×(-2)-3-1/2×(-2)×3-6】
=-6×【-6-3+3-6】
=-6×(-12)
=72
已知(a+2)²+(3-b)的绝对值=0,
a+2=0 a=-2
3-b=0 b=3
3a²b-【2ab²-b(ab-1/2a²b)+4ab】-2ab
=3a²b-【2ab²-ab²+1/2a²b²+4ab】-2ab
=3a²b-2ab²+ab²-1/2a²b²-4ab-2ab
=3a²b-ab²-1/2a²b²-6ab
=ab(3a-b-1/2ab-6)
=-2×3×【3×(-2)-3-1/2×(-2)×3-6】
=-6×【-6-3+3-6】
=-6×(-12)
=72