1/a+1/b=(a+b)/(ab)=1/(a+b)
ab=(a+b)2
ab=a2+2ab+b2
a2+b2 =-ab
b/a+a/b=(b2+a2)/(ab)=-ab/ab=-1
第二题
s/a=v1-v2
s/b=v1+v2
v1=(1/a+1/b)*(s/2)
v2=(1/b-1/a)*(s/2)
v1/v2=(a+b)/(a-b)
1/a+1/b=(a+b)/(ab)=1/(a+b)
ab=(a+b)2
ab=a2+2ab+b2
a2+b2 =-ab
b/a+a/b=(b2+a2)/(ab)=-ab/ab=-1
第二题
s/a=v1-v2
s/b=v1+v2
v1=(1/a+1/b)*(s/2)
v2=(1/b-1/a)*(s/2)
v1/v2=(a+b)/(a-b)