Question

若|a+2|+b^2-2b+1=0,求代数式[(2a+b)^2+(2a+b)(b-2a)-6b]/2b的值.快,急.

Answer 1

|a+2|+b^2-2b+1=0

|a+2|+(b-1)^2=0

a=-2,b=1

[(2a+b)^2+(2a+b)(b-2a)-6b]/2b

=[(2a+b)^2-(2a+b)(2a-b)-6b]/2b

=(4a^2+4ab+b^2-4a^2+b^2-6b)/2b

=(2b^2+4ab-6b)/2b

=b+2a-3

=1-4-3

=-6