有没有问题?
题目是不是化简：(sin2x＋2sin²x)/(1＋tanx)
(sin2x＋2sin²x)/(1＋tanx)
=[2sinxcosx(sinx＋cosx)]/[cosx＋sinx]
=2sinxcosx
=sin2x
化简(sin2x+2sin^2 x)/1-tanx
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