4x²+4x-9y²+1=0
(2x+1)²-9y²=0
y²=(2x+1)²/9
(2x+1)²/9-2x-1=0
4x²-14x-8=0
2x²-7x-4=0
(2x+1)(x-4)=0
2x+1=0 x=-1/2 y=0
x-4=0 x=4 y=±3
所以x=-1/2 y=0 或x=4 y=3或x=4 y=-3
4X^2+4X-9Y^2+1=0,Y^2-2X-1=0,求X,
1个回答
相关问题
-
1.2x+3y-2=0 4x-9y+1=0 2.2x+y=2 3x-2y=10
-
解下列方程组（1）x2/4-y2=1,x-y-2=0:(2)(x-3)2+y2=9,x+2y=0
-
1.已知x^2+2x+1+y^2-4y+4=0,求x,y.
-
若|x+2y-1|+y²+4y+4=0,求（2x-y）²-2（2x-y)(x+2y)+(x+2y)&
-
1）已知x^2+y^2-2x+4y+5=0,求x^4-y^4/(x+y)(2x-y)`2x-y/x
-
马上就要答案,（x-1）2+2x（x-1）=0 2x2-4x-5=0 -3x2-4x+4=0 2(y+4)2+y(y+4
-
4分之x－y＝﹣1 x＋4y＝4,求x,y 0.2x＋0.5y＝5分之1 0.4x＋0.1y＝5分之2,求x,y
-
（x+2y-1)^2+I 2x-y-2 I^2=0 求4（2x-y)^2-2(2x-y)(2x+y)+4/1(2x+y)
-
(1)y=x,y+4x=15; (2)x+2x-3y=1; (3)x-7y=0,x-9y=8=0.
-
1.求y=3^(x-1)-2 (x1)值域 2.求y=log1/2(x^2-4x+5)值域 3.y=0(x>=0);y=