tanA*tanB/(tanA+tanB)=1004tanC得
(sinAsinB)/(sinAcosB+sinBcosA)=1004sinC/cosC
采用正弦定理(ab)/(acosB+bcosA)=1004c/cosC
采用余弦定理化简得(ab)/c=1004c/[(a^2+b^2-c^2)/(2ab)]
a^2+b^2-c^2=2008c^2
a^2+b^2=2009c^2
所以m=2009,选C
tanA*tanB/(tanA+tanB)=1004tanC得
(sinAsinB)/(sinAcosB+sinBcosA)=1004sinC/cosC
采用正弦定理(ab)/(acosB+bcosA)=1004c/cosC
采用余弦定理化简得(ab)/c=1004c/[(a^2+b^2-c^2)/(2ab)]
a^2+b^2-c^2=2008c^2
a^2+b^2=2009c^2
所以m=2009,选C